Find the index in a circular array from which prefix sum is always non-negative

Find the index in a circular array from which prefix sum is always non-negativeGiven a circular array arr[] consisting of N integers, the task is to find the starting index of the circular array such that the prefix sum from that index is always non-negative. If there exists no such index, then print “-1”.Examples:Input: arr[] = {3, -6, 7, -1, -4, 5, -1}Output: 2Explanation:Consider the index 2 from where the prefix sum of the given circular array is being calculated, then the prefix sum is given by {9, 3, 7, 6, 2, 7, 6}Input: arr[] = {3, -5, -1}Output: -1Approach: The given problem can be solved based on the following observations:Follow the steps to solve the problem:Initialize a variable, say sum as 0, that stores the sum of array elements.Initialize a variable, say in as 0 that stores the starting index for the circular traversal.Initialize a variable, say min as INT_MAX that stores the minimum prefix sum of the array arr[].Traverse the given array and perform the following steps:Update the value of sum as the sum of sum and the current element arr[i].If the value of sum is less than min, then update the min as sum and in as (i + 1).If the sum of the array is negative, then print -1. Otherwise, print the value of (in % N) as the resultant possible index.Below is the implementation of the above approach:C++  #include using namespace std;  int startingPoint(int A[], int N){        int sum = 0;          int in = 0;              int min = INT_MAX;          for (int i = 0; i < N; i++) {                  sum += A[i];                  if (sum < min) {                                      min = sum;                          in = i + 1;        }    }              if (sum < 0) {        return -1;    }      return in % N;}  int main(){    int arr[] = { 3, -6, 7, -4, -4, 6, -1 };    int N = (sizeof(arr) / sizeof(arr[0]));    cout